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4. ANOVA calculations and rejection of the null hypothesis The following table summarizes the results of a study on SAT prep
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Private High school No prep Total
Count, n 40 40 40 120
Mean 610 600 590
Sum of square,SS 97500 101400 111150 0

Grand mean = (610+600+590)/3 = 600

Number of treatment, k = 3

Total sample Size, N =120

df(between) = k-1 =2

df(within) = N-k =117

df(total) = N-1 =119

SS(between) = (x̅1)²*n1 + (x̅2)²*n2 + (x̅3)²*n3 - (Grand Mean)²*N = 8000

SS(within) = SS1 + SS2 + SS3 = 310050

SS(total) = SS(between) + SS(within) =318050

MS(between) = SS(between)/df(between) =4000

MS(within) = SS(within)/df(within) =2650

Source of variation SS df MS
Between Groups 8000 2 4000
Within Groups 310050 117 2650

The SStotal is sometimes easier to calculate than SSbetween . Since SSwithin + SSbetween = SStotal, you can use SStotal to calculate SS between.

In ANOVA, the F test statistic is the ration of the between-treatments variance and the within-treatments variance. The value the F test statistic is:

F = MS(between)/MS(within) = 1.5094

When the null hypothesis is true, The F test statistic is around 1.

When the null hypothesis is false, The F test statistic is most likely to be more than the F critical value at given significance value.

In general you should reject the null hypothesis for F value greater than the F critical value at given significance value.

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