1. Number of treatments = Treatment degrees of freedom + 1 = (45 - 22) + 1 = 24
F - calculated = MST / MSE = (12.2/24) / (92.4/22) = 0.12
So Fail to reject Ho
Hence,
Answer will be:
24; FR
QUESTION 4 The following is the ANOVA data obtained from a balanced CRD: ANOVA: Source of...
Apply the techniques of two-way ANOVA to a data sample split into eight treatments with total degrees of freedom, df = 47, testing at the 2.5% level of significance. The Sum of Squares for Treatments is 42; the Mean Square for Blocks is 9, and the Mean Square for Error is 3. SS df MS F test Stats Treatments #1 #5 #9 #12 Blocks #2 #6 #10 #13 Error #3 #7 #11 XXXXXXX Total #4 #8 XXXXXXX XXXXXXX #14: What...
Question Completion Status QUESTION 4 Anova: Single Factor SUMMARY Groups Count Sum Average Variance A 4 108 27 32.66666667 B 4 96 24 13.33333333 4 120 30 56 ANOVA Source of Variation SS df F crit MS P-value F Treatments 72 36 1.058823529 0.386396621 4.256494729 Error 306 9 34 Total 378 11 Based on the Results above of Single Factor ANOVA: the MSTR O 36 O 378 O 72 O 34 Click Save and Submit to save and submit. Chick...
7. The following ANOVA table was obtained from a balanced completely randomized design: 1) Complete the ANOVA table Compl SS Source Treatments Error Total (corrected) 99 900 999 2) Determine the number of treatments 3) Determine the number of replications per treatment. What is the F value? 5) What is the value of R??
1. The following ANOVA summary table was obtained for a comparison of six teachers. Of interest is whether students of those teachers display different mean levels of performance on a standardized language test. Class size is about 20 to 22 students per teacher, for a total number of 126 students included in the analysis. a. Complete the missing calculations in the table below. (0.5 points each; 3 points total) Sum of Squares df Mean Square F Between Groups 600.00 _____?...
Please help with the following multiple choice 1. In the one-way ANOVA where there are k treatments and n observations, the degrees of freedom for the F-statistic are equal to, respectively: a. n and k. b. k and n. c. n − k and k − 1. d. k − 1 and n − k. 2. In ANOVA, the F-test is the ratio of two sample variances. In the one-way ANOVA (completely randomized design), the variance used as a numerator...
The following data are from a completely randomized design. Treatment 145 145 145 149134 151 140 129 Sample mean Sample variance a. Compute the sum of squares between treatments. 159 310 142 108.8 134 145.2 b. Compute the mean square between treatments. c. Compute the sum of squares due to error d. Compute the mean square due to error (to 1 decimal), e. Set up the ANOVA table for this problem. Round all Sum of Squares to nearest whole numbers....
please answer all fill in the blank Keep the Highest: Attempts: /4.5 7. Comparing ANOVA and the t test for an independent-measures hypothesis test Aa Aa Suzanne Zeedyk, a developmental psychologist at Dundee University's School of Psychology, conducted a pilot study in which parents started a half-hour walk with their infants in a parent-facing or an away-facing stroller and then switched to the other type of stroller midway. Her results suggest that parents talked less to the babies, the babies...
The following data were obtained for a randomized block design involving five treatments and three blocks: SST = 490, SSTR = 310, SSBL = 95. Set up the ANOVA table. (Round your value for F to two decimal places, and your p-value to three decimal places.) Source of Variation Sum of Squares Degrees of Freedom Mean Square F p-value Treatments Blocks Error Total Test for any significant differences. Use α = 0.05. State the null and alternative hypotheses. H0: At...
The following data are from a completely randomized design. Treatment 164 149 142 157 167 124 145 149 149 137 169 136 156 142 144 141.6 119.6 126 122 133 141 152 130 134 Sample mean Sample variance a. Compute the sum of squares between treatments. Round the intermediate calculations to whole number 1488 b. Compute the mean squ are between treatments. 744 c. Compute the sum of squares due to error. 135.33 d. Compute the mean square due to...
4. Repeated-measures ANOVA Aa Aa Suppose you are interested in studying whether lighting brightness affects spatial reasoning abilities. You decide to test spatial reasoning using completion time scores for the paper-folding test with five people, repeating the test on each person with three different lighting levels (800, 1,000, and 1,200 lux) In this experiment, the null hypothesis is that: O There are no individual differences in the completion time means O The completion time mean for at least one lighting...