The following data are from a completely randomized design. Treatment 145 145 145 149134 151 140...
The following data are from a completely randomized design. Treatment 163 145 123 142 157 121 166 129 132 144 145 144 148 138 153 191 138 131 159 142 134 344.8 88.8 152.8 Sample mean Sample variance a. Compute the sum of squares between treatments. Round the intermediate calculations to whole number. b. Compute the mean square between treatments. c. Compute the sum of squares due to error. d. Compute the mean square due to error (to 1 decimal).
The following data are from a completely randomized design. A 164, 142, 169, 145, 149, 167 Sample mean 156 Sample variance 144. B 147, 156,127, 147, 131, 144 Sample mean 142 Sample variance 119.2 C 124, 121, 134, 141, 158, 126, sample mean 134 sample variance 191.6. (1) Compute the sum of squares between treatments. (2) Compute the mean square between treatments. (3) Compute the sum of squares due to error. (4) Compute the mean square due to error (to...
The following data are from a completely randomized design. Treatment 164 149 142 157 167 124 145 149 149 137 169 136 156 142 144 141.6 119.6 126 122 133 141 152 130 134 Sample mean Sample variance a. Compute the sum of squares between treatments. Round the intermediate calculations to whole number 1488 b. Compute the mean squ are between treatments. 744 c. Compute the sum of squares due to error. 135.33 d. Compute the mean square due to...
e. Set up the ANOVA table for this problem. Round all Sum of Squares to nearest whole numbers. Round all Mean Squares to one decimal places. Round F to two decimal places. Source of Variation Sum of Squares Degrees of Freedom Mean Square F Treatments Error Total f. At the α-.05 level of significance, test whether the means for the three treatments are equal The p-value is less than.01 What is your conclusion? Select The following data are from a...
The following data are from a completely randomized design. Treatment Treatment Treatment A B C 32 47 34 30 46 37 30 47 36 26 49 37 32 51 41 Sample mean 30 48 37 Sample variance 6 4 6.5 At the = .05 level of significance, can we reject the null hypothesis that the means of the three treatments are equal? Compute the values below (to 1 decimal, if necessary). Sum of Squares, Treatment Sum of Squares, Error Mean...
The following data are from a completely randomized design. Treatment Treatment Treatment 32 30 30 26 32 30 35 38 37 38 42 38 6.5 45 45 47 49 46 Sample mean Sample variance At the α-.05 level of significance, can we reject the null hypothesis that the means of the three treatments are equal? Compute the values below (to 1 decimal, if necessary). Sum of Squares, Treatment Sum of Squares, Error Mean Squares, Treatment Mean Squares, Error
In a completely randomized design, 12 experimental units were used for the first treatment, 15 for the second treatment, and 20 for the third treatment. Complete the following analysis of variance (to 2 decimals, if necessary). Round p-value to four decimal places. If your answer is zero enter "0". Source of Variation Sum of Squares Degrees of Freedom Mean Square F p-value Treatments 1,300 --?-- --?-- ----?----- ---?------ ----?---- Error --?-- --?-- --?-- ----?----- ---?------ ----?---- Total 2,000 ...
In a completely randomized design, 12 experimental units were used for the first treatment, 15 for the second treatment, and 20 for the third treatment. Complete the following analysis of variance (to 2 decimals, if necessary). Round p-value to four decimal places. If your answer is zero enter "0". Source of Variation Sum of Squares Degrees of Freedom Mean Square p-value Treatments 1,100 Error Total 1,900 At a .05 level of significance, is there a significant difference between the treatments?...
The following data are from a completely randomized design. In the following calculations, use a = 0.05. Treatment Treatment Treatment 88 77 ł / 51 58 132.67 113.33 54.00 a. Use analysis of variance to test for a significant difference among the means of the three treatments. Source of Variation Sum of Squares Degrees Mean Square p-value (to whole number of (to whole number) bers (to 2 decimals) to - decimals (to 3 decimals) Freedom Treatments Error Total The p-value...
In a completely randomized design, seven experimental units were used for each of the five levels of the factor. Complete the following ANOVA table (to 2 decimals, if necessary). Round p-value to four decimal places. If your answer is zero enter "0". F p-value Source of Variation Sum of Squares Degrees of Freedom Mean Square Treatments 300 Error Total 460 a. What hypotheses are implied in this problem? Ho: Select H. Select b. At the - .05 level of significance,...