Question

Apply the techniques of two-way ANOVA to a data sample split into eight treatments with total degrees of freedom, df = 47, testing at the 2.5% level of significance. The Sum of Squares for Treatments...

Apply the techniques of two-way ANOVA to a data sample split into eight treatments with total degrees of freedom, df = 47, testing at the 2.5% level of significance. The Sum of Squares for Treatments is 42; the Mean Square for Blocks is 9, and the Mean Square for Error is 3.

SS df MS F test Stats
Treatments #1 #5 #9 #12
Blocks #2 #6 #10 #13
Error #3 #7 #11 XXXXXXX
Total #4 #8 XXXXXXX XXXXXXX

#14: What is the F critical for treatments, rounding to the nearest ten-thousandths? [COMMENTS & HINTS: It is a number between zero and ten. Enter this answer as #.####]

#15: What is the F critical for blocks, rounding to the nearest ten-thousandths? [COMMENTS & HINTS: It is a number between zero and ten. Enter this answer as #.####]

#16: What is the most appropriate technical conclusion for treatments, based on the available evidence and testing at the indicated level of significance? {Select the best response.}

a) The researcher would highly reject the unidentified null hypothesis.    b) The researcher would reject the unidentified null hypothesis. c) The researcher would marginally reject the unidentified null hypothesis.    d) The researcher would highly fail to reject the unidentified null hypothesis. e) The researcher would fail to reject the unidentified null hypothesis. f) The researcher would marginally fail to reject the unidentified null hypothesis.

#17: What is the most appropriate technical conclusion for blocks, based on the available evidence and testing at the indicated level of significance? {Select the best response.}

a) The researcher would highly reject the unidentified null hypothesis. b) The researcher would reject the unidentified null hypothesis. c) The researcher would marginally reject the unidentified null hypothesis.    d) The researcher would highly fail to reject the unidentified null hypothesis. e) The researcher would fail to reject the unidentified null hypothesis.    f) The researcher would marginally fail to reject the unidentified null hypothesis.

#18: What is the total sample size, n?

#19: What is the p-value, reported to four decimal places, for treatments?

#20: What is the p-value, reported to four decimal places, for blocks?

#21: What is the number of blocks?

0 0
Add a comment Improve this question Transcribed image text
Answer #1

SOLUTION

The completed table is,

Source SS df MS F
Treatments 42 7 6 2
Blocks 45 5 9 3
Error 105 35 3
Total 192 47

df for Treatments = Number of treatments - 1 = 8 - 1 = 7

Total number of observations = df Total + 1 = 47 + 1 = 48

Number of blocks = Total number of observations / Number of treatments = 48 / 8 = 6

df for Blocks = Number of blocks - 1 = 6 - 1 = 5

df for Error = df Total - (df treatments + df Blocks) = 47 - (7 + 5) = 35

SS = MS * df for Blocks , Error

SS Total = SS Treatments + SS Block + SS error = 42 + 45 + 105 = 192

MS Treatments = SS Treatments / df Treatments = 42 / 7 = 6

F = MS / MS Error for Treatments and Blocks

14.

For Treatments,

Numerator df = df Treatments = 7

Denominator df = df Error = 35

Critical value of F at df = 7, 35 and 2.5% level of significance is 2.6755

15.

For Blocks,

Numerator df = df Blocks = 5

Denominator df = df Error = 35

Critical value of F at df = 5, 35 and 2.5% level of significance is 2.9557

16.

P-value = P(F > 2, df = 7,35) = 0.0831

Since F for Treatments (2) is less than the critical value of 2.6755, and p-value is under 0.1 but greater than 0.025,

e) The researcher would fail to reject the unidentified null hypothesis

17.

P-value = P(F > 3, df = 5,35) = 0.0234

Since F for Blocks (3) is greater than the critical value of 2.9557, and p-value is just less than 0.025,

c) The researcher would marginally reject the unidentified null hypothesis

18.

Total sample size, n = df Total + 1 = 47 + 1 = 48

19.

P-value for treatments,

P-value = P(F > 2, df = 7,35) = 0.0831

20.

P-value for blocks,

P-value = P(F > 3, df = 5,35) = 0.0234

21.

Number of blocks = 6 (Calculated above)

Add a comment
Know the answer?
Add Answer to:
Apply the techniques of two-way ANOVA to a data sample split into eight treatments with total degrees of freedom, df = 47, testing at the 2.5% level of significance. The Sum of Squares for Treatments...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Source Between treatments Within treatments Sum of Squares (Ss) df Mean Square (MS) 2 310,050.00 2,650.00 In some ANOVA summary tables you will see, the labels in the first (source) column are Treatm...

    Source Between treatments Within treatments Sum of Squares (Ss) df Mean Square (MS) 2 310,050.00 2,650.00 In some ANOVA summary tables you will see, the labels in the first (source) column are Treatment, Error, and Total Which of the following reasons best explains why the within-treatments sum of squares is sometimes referred to as the "error sum of squares"? O Differences among members of the sample who received the same treatment occur when the researcher O Differences among members of...

  • 5. Hypothesis testing with ANOVA Aa Aa E Opinions about whether caffeine enhances test performance differ....

    5. Hypothesis testing with ANOVA Aa Aa E Opinions about whether caffeine enhances test performance differ. You design a study to test the impact of drinks with different caffeine contents on students' test-taking abilities. You choose 21 students at random from your introductory psychology course to participate in your study. You randomly assign each student to one of three drinks, each with a different caffeine concentration, such that there are seven students assigned to each drink. You then give each...

  • A researcher wants to determine if the number of years of education that a person's father...

    A researcher wants to determine if the number of years of education that a person's father has ("paeduc") is related to the number of years of education that the person has ("educ"). He uses simple linear regression to examine this question. The output from Excel is shown below. Regression Statistics Multiple R 0.527393938 R Square 0.278144366 Adjusted R Square 0.264776669 Standard Error 2.436826202 Observations 56 ANOVA df F Significance F 2.96139E-05 20.8072 Regression Residual Total SS MS 123.555701 123.5557 320.6585847...

  • The following ANOVA model is for a multiple regression model with two independent variables: Degrees of            Sum of                 Mean Source           Freedom            Squares              ...

    The following ANOVA model is for a multiple regression model with two independent variables: Degrees of            Sum of                 Mean Source           Freedom            Squares                Squares       F       Regression            2                    60 Error                   18                 120 Total                   20                 180 Determine the Regression Mean Square (MSR): Determine the Mean Square Error (MSE): Compute the overall Fstat test statistic. Is the Fstat significant at the 0.05 level? A linear regression was run on auto sales relative to consumer income. The Regression Sum of Squares (SSR) was 360 and...

  • 2. An experiment was conducted to compare five treatments for reducing fever. Thirty-five patients were randomly...

    2. An experiment was conducted to compare five treatments for reducing fever. Thirty-five patients were randomly assigned into five treatment groups. The patients' temperatures were taken two hours after receiving the treatment, and are given below. We will test the claim that there is no difference in mean body temperature among each of the five treatment groups using a 5% significance level. Placebo Aspirin Anacin Tylenol Bufferin 98.3 96.0 97.2 95.1 96.1 98.7 96.6 97.4 95.7 96.5 98.1 95.3 96.9...

  • Q2. Hypothesis Testing with a Z test (14 points total) A research institute examined the number...

    Q2. Hypothesis Testing with a Z test (14 points total) A research institute examined the number of smart phones and tablets connected to the internet in American households and reported a mean (μ) of 5 devices per household and a standard deviation (σ) of 1.5 devices. But I wonder if the statistics in my neighborhood, Chandler, would be different from the national average. To test this idea, I randomly picked 16 friends of mine living in Chandler and asked them...

  • stats Q2. Hypothesis Testing with a Z test (14 points total) A research institute examined the...

    stats Q2. Hypothesis Testing with a Z test (14 points total) A research institute examined the number of smart phones and tablets connected to the internet in American households and reported a mean (μ) of 5 devices per household and a standard deviation (σ) of 1.5 devices. But I wonder if the statistics in my neighborhood, Chandler, would be different from the national average. To test this idea, I randomly picked 16 friends of mine living in Chandler and asked...

  • Timerl The medical researcher is comparing two treatments for lowering cholesterol: diet and meds...

    Timerl The medical researcher is comparing two treatments for lowering cholesterol: diet and meds. The researcher wants to see if the patients who receive the recommendation to change their diet have less success lowering cholesterol compared to a prescription of meds. A random sample of some patients who received the recommendation to change their diet and others who were prescribed meds was taken. The results of how many did or did not lower their cholesterol are shown below: Data on...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT