Homework Answers
force between A and B is given by
Fab = k * 1.3* 7.3* 10^-12 / 0.5^2
Fab = 0.3416 N
force between A and C is
Fac = 9*10^9* 1.3* 4.08*10^-12 / 0.5^2
Fac = 0.1909 N
Angle between Fac and Fab = x = 180 - 60 = 120
net force acting on 1.3 uC
F^2 = Fab^2 + Fac^2 + 2 Fab Fac cos x
F^2 = 0.3416^2 + 0.1909^2 + 2* 0.3416*0.1909* cos 120
F = 0.2965 N
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