write the balanced equation for this reaction and calculate the percentage yield.
write the balanced equation for this reaction and calculate the percentage yield. Iron (I) Chloride hexahydrate...
write a balanced equation for this reaction and calculate the percentage yield of the product. (FeCl3.6420) tron (II) Chloride hexahydrate 1.64g } A 13 mL H2O add solution B to A Talg acetylacerone 5 mL methonal JB acetate I add to A+B mixture 2.56g of Sodium 8nh H₂O gives yeild of 157g of Fe (Cs H₂O2)
c. Given an actual yield of 0.99 g iron(II) oxalate, FeC204.2H20, calculate the percentage yield SO.) 6H0+ 2. H.C.O. - fear 2 C-2 - 2 16 FeC20:2H20 +_SH.C.O. + 2 FeC.0, 2H,0 + (NH) SO. + _H.SO. + H0 Fe- 1 0 =15 S=2 H2O2+ 3.KC,8. - K [Fe(COT 3H30 Transfer the balanced chemical reactions to page 6. 4. Use the first of the above balanced chemical equations to determine the following a. The reaction mixture initially contains 2.5 of...
1 U UIO 1. Write the balanced equation for the reaction of nickel(II) chloride hexahydrate when heated. 2. Write the balanced equation for the reaction of hydrochloric acid and sodium carbonate.
Irom metal reacts with chlorine gas giving iron(II) chloride. The balanced chemical equationfor this reaction is: 2 Fe(s) 3 C12(g) 2 FeCl3(s) 75.5 g FeCl, can be produced from 26.0 g of iron and excess Clh. If only 21.3 g of FeCly is obtained, what is the percent yield?
2. (2 points) Calculate the percentage of Fe in pure iron(I) ammonium sulfate hexahydrate: (NH4)2[Fe(SO4)2]. 6 H2O.
- Determine the theoretical yield in grams of iron(II) oxalate dihydrate, FeC204.2H20. Balance the following chemical equations: Feat =R2 N- Fe(NH)-(SO)2 + 6H-0+ 2.H.C0. - 2 FC 02H0+ (NH.)50. + HS0+ & HO H=22 N=2 C2 Fel 0=15 S=2 FeC204. 2H2O + H2C2O4 + H2O2 + 3 K.CO. - KiſFcc0bf-3H30 Transfer the balanced chemical reactions to page 6. 4. Use the first of the above balanced chemical equations to determine the following a. The reaction mixture initially contains 2.5 g...
51 3. Hydroxylammonium chloride reacts with iron(lIl) chloride, FeCl, in solution to produce iron(I) chloride, HCl, H,O, and a compound of nitrogen. It was found that 2.00g of iron(II) chioride reacted in this way with 31.0 mL of 0.200M hydroxylammonium chloride. Suggest a possible formula for the compound of nitrogen so produced. This should be a known nitrogen compound. 4. Arsenic(II) oxide, As,O3, can be titrated with potassium bromate in aqueous solution to produce potassium bromide and arsenic acid, H,AsO,....
Write a balanced molecular equation for the reaction that occurs when aqueous solutions of iron(II) chloride and lithium hydroxide react to form aqueous lithium chloride and an iron(II) hydroxide precipitate. FeCl2(aq) + LiOH(aq) → Fe(OH)2(s) + LiCl(aq) You have the reactants and products correct! Great job! But the chemical equation is not balanced. FeCl2(aq) + 2 LiOH(aq) → Fe(OH)2(aq) + 2 LiCl(aq) 2 FeCl2(aq) + LiOH(aq) → 2 Fe(OH)2(s) + LiCl(aq) FeCl2(aq) + 2 LiOH(aq) →...
1. Add sodium hydroxide to iron(II) chloride iron(IlWl) hydraxide sodium chioride ppr 3 NaOH(ag)+ FeCls (aq) -→ Fe(OHhds) + 3 Naa (aq) 2. Mix lead(I) acetate lead waste and potassium iodide 3. Mix copper(l) sulfate and sodium hydroxide copper waste 4. Mix sulfuric acid (3M) and sodium hydroxide 5. Mix magnesium chloride and sodium carbonate 6. Mix aluminum nitrate pe+ and potassium carbonate 7. Mix copper(II) nitrate and potassium iodate pp午 copper waste CaCO3 waste 8. Add hydrochloric acid rRt...
17. On the basis of the general solubility rules given in Table 7.1, write a balanced molecular equation for the precipitation reactions that take place when the following aqueous solutions are mixed. Underline the formula of the precipitate (solid) that forms. If no precipitation reaction is likely for the reactants given, explain why. a. ammonium chloride, NH,CI, and sulfuric acid, H,SO b. potassium carbonate, K,CO3, and tin(IV) chloride, Snc c. ammonium chloride, NH CI, and lead(II) nitrate, Pb(NO3) d. copper(II)...