Question

Problem 7.7 The melting of sold ice to give liquid water has AH-144 kcal/ mol(+602 kJ/mol and AS -5.25 cal/mol.K) (220 J/(mol )) What is the value of AG for the melting process at the following temperatures? SC (265) Express your answer using two decimal places. 10 A4 OE? AG- kcal/mol kJ/mol Subm Beguest Answer Part B Is the melting spontaneous or nonspontaneous at -10° 283 K spontaneous nospontaneous in equilibrium Submit Neuts or nonpontaneous at 0273 )

Answer 1

Date Given i ol = +1.44 kcal mol =+6.02 KJ 1 mol Page No.: or +1.44 x 10 call mal or +6.028 103 J1 mol AS = +5,26 cal molk = + 22.0 J/molk for the OG reaction is given of melting of ice into water DG=AU - TAS , nergy where To A4 = 4 All = Enthalpy change AS = Entropy change T = Temperature in Kelvin - ort (A AG at -8°c (265k) - putting values of DH & as in calorie unit DG = 1.44X10 Call mol - 265k X 5.26 Callmolk - = 46.1 call mol TAG = 0.461 kcal/mol . Now Now putting all values in other units, pun s4= 6.62% 10 Jl mal - 265 KX 22.0 J/molk = 190 J/mol 1 DG = 0.190 kj

Date __I_ A Page No. Part (B) for a reaction, if D4<0 , Reaction is spontaneous if Da>0, Reaction is Non - spontaneous if OG=0, Reaction is at equilibrium, AG at -10°c (263k) DG = 6.02% 10 Jmol - 263k X 22.0 T molk AG = 234 J mol Here, 0630 so S Reaction is Non - spontaneous. Part (c) AG at oc (2736) - SG = 6:02x 10 Jmol - 273k X 22.0 I molk = 14 J/mol Here also DGO Reaction is Non-spontaneous.