Question

Student Handout: S2/"PNMR Lab Report Your la report should come the following pieces of Wormation 1. Atable reporting the following a. The product/reactant/wide crude intration data observed by HP NMR for your The product/reactante crude integration data de NMR for the other three reactions done by your group. The product/reactant/wide ratio observed by NMR for your reaction. d. The product reactantiderate observed by NMR for the other the reactions done by your group. 2. Using the row.pushing formalium, draw the mechanism for the transformation of your phosphine into the phosphonium salt you observed by PNMR. 3. A brief written component answering the following questions a. Based on your collected data, is 1-bromobutane or 2-bromobutane a more active electrophile? How do you explain this observation? b. Based on your collected data s PPh, or Pillu, a more active rucleophie? How do you explain this observation? Musly and rura Readion A Br + aceton, frile (1.5 mL) fo Cous mu) Phosphonium Salt Phosphine vide Unreacted phosphine Go.23 Reaction A Reaction B ЧИ СО 185.32 189.7 21676 laol.4 Reaction D 67.67 136.71 Product Ratios Phosphonium Salt 11.92 Phosphine Oxide 1.690 Reaction A Reaction Reactionc Reaction D Unreacted phosphine 89.5% 009 0 .45 9 - 32.65% 31.1290 77,35 7.182 The product ratios determined for these four reactions will be used to answer the questions presented in the Lab Report.

i need help with 2 and 3 please

Answer 1

2. (Phpin + Acetonidae (1.5 mi) ® en case of simple nucleophte substitution reaction, (SNR) primany cintor is more reactive than the secondary center (electrophilic) because secondary electrophilie center is more herically hindered thew primary center. a la By uss hindered center - Morne hindered so, 1. Bromo butane is more active conter - electrophile ② for this case, the lone pair of PPhz is de localized over three phenyl rings, so, nucles philicity of dereased. But in case of P (Bu) z low pair is bealized sete E po so. P(Bu), is more active nude ostile than pena