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ation fects 2.31 The graph in Fig. E2.31 shows the velocity of a motor- cycle police officer plotted as a function of time. (a) Find the instantaneous acceleration at t=3 s, t=7 s, and t= 11 s. not car(b) How far does the officer go in the first 5 s? The first 9 s? The s of first 13 s? ur- to Figure E2.31 LH ave ct. To pe er at Ux (m/s) 50 45 40 35 30 25 20 15 10 1S t (s) 0 2 4 6 8 10 12 14
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Answer #1

We can use the graph given to find the instantaneous acceleration of vehicle as the rate of change of velocity is acceleration. And in second question we can ise equation of motion with constant acceleration to find the distance covered.

Calculation is as shown below.

Gr ian: velocit Vs time aa h acceleration at t 3s instantaneoug acc e lens a tion is凸iven by, aう.instantarv elacity m e diaecton Ol At tus b) Dis tance travelled in →fast 5 second distance : 20 うに,。。m x5s : 100m, wilt fnd the area unde cusve to find the distan e e Piost 13 sec 25 m Soistanee 32 Sm

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