Question

Consider the approximately normal population of heights male college students with mean = 74 invhes and standard deviation = 6.2 inches. A random sample of 10 heights is obtained.

(b) Find the proportion of male college students whose height is greater than 74 inches (Give your answer correct to four decimal places.) X (c) Describe the distribution of x, the mean of samples of size 10. skewed right approximately normal skewed left chi-square (d) Find the mean of the x distribution. (Give your answer correct to the nearest whole number.) (e) Find the standard error of the distribution. (Give your answer correct to two decimal places.) (1) Find P(x > 69). (Give your answer correct to four decimal places.) (9) Find PCX < 67), (Give your answer correct to four decimal places.) journal2.jpg

Answer 1

Solution from gim dlake. м: 74 6--62 n=10 (bu Now we have to find out the P(Z > 74) = ? P(x3 zu) = Ple inserire .:P(Z > 1966 ) Plzsoj Plasu): 0.5 Solo find the mean of the I distribution to the Mean (Mai): M E TA I Mx : 74 find the standard Eumor of the di distribution Cel = 1.9605 1:96 i so, the standard Error of the 5 distribution is -> 1.96.

POX > 69) ? PC >69). PA - Mi 69 - Plz 1 an . 69 - 74 1 1.96 EP17> 69.9.2014.) ap/2 = 55 ) PIZ >-2.5510) 1-P172-2.5510) +1 -0.00537 Pli>69) = 0.9946] .. so, the required probe.bility sy 30.9946. (9) find out P( 2 <67) = ? Plà267) = P(XIME c 67-May . .plz z 67-74 ) :P(Z < 26 ) 1.96 ) - P(Z <-3-5714) 0.0001775 0.0002 | Pla267) = 0.0002 ². So, the required probability G 0.0002 ,