A) Find the moment of inertia of a 2 meter long stick with a mass of 14 kg, if it is spun about the center of the stick
B) Find the rotational kinetic energy of a spinning (not rolling) bowling ball that has a mass of 7 kg and a radius of 0.10 m moving at 7 m/s.
HINT: v = rω
C) An ice skater with a moment of inertia of 10 kg m2 spinning at 19 rad/s extends her arms, thereby changing her moment of inertia to 33 kg m2. Find the new angular velocity.
Hint: conserve angular momentum
A) Find the moment of inertia of a 2 meter long stick with a mass of...
An ice skater with moment of inertia 70.0 kg•m2 is spinning at 41.0 rpm. If the skater pulls in her arms, her moment of inertia decreases to 50.0 kg•m2. What is the skater’s resulting angular velocity?
An ice skater is spinning at 2.5 revolutions per second and has a moment of inertia of 0.85 kg m2. Estimate her rotational angular momentum, assuming for simplicity that she can be approximated as a rigid, axially-symmetric body.
An ice skater is spinning at 6.8 rev/s and has a moment of inertia of 0.24 kg ⋅ m2. Calculate the angular momentum, in kilogram meters squared per second, of the ice skater spinning at 6.8 rev/s. He reduces his rate of rotation by extending his arms and increasing his moment of inertia. Find the value of his moment of inertia (in kilogram meters squared) if his rate of rotation decreases to 1.25 rev/s. Suppose instead he keeps his arms...
Calculate the moment of inertia for each scenario: (a) An 80.0 kg skater is approximated as a cylinder with a 0.140 m radius. (b) The skater extends both her arms, each of which is approximated as a 4.00 kg rod with length 0.850 m rotated about its end. (c) Calculate the angular velocity of the skater during scenario (b) if her angular velocity during scenario (a) is 6.75 rad/s.
6. a) A 4.0-kg block starts from rest on the positive z axis 5.0 m from the origin and thereafter has an acceleration given by À = 3i+5k in m's? Find its angular momentum at the end of 3.0 s about the origin: b) A figure skater rotating at 5.00 rad/s with arms extended has a moment of inertia of 2.25 kg. m2. If the arms are pulled in so the moment of inertia decreases to 1.80 kg • m2,...
An ice skater has a moment of inertia of 5.0 kg-m2 when her arms are outstretched. At this time she is spinning at 3.0 revolutions per second (rps). If she pulls in her arms and decreases her moment of inertia to 2.0 kg-m2, how fast will she be spinning? A) 7.5 rps B) 8.4 rps C) 2.0 rps D) 10 rps E) 3.3 rps
Calculate the angular momentum, in kg · m2/s, of an ice skater spinning at 6.00 rev/s given his moment of inertia is 0.330 kg · m2. (a) Calculate the angular momentum, in kg . m/s, of an ice skater spinning at 6.00 rev/s given his moment of inertia is 0.330 kg . m2. kg. m/s (b) He reduces his rate of spin (his angular velocity) by extending his arms and increasing his moment of inertia. Find the value of his...
Problem 19: An ice skater is spinning at 6.2 rev/s and has a moment of inertia of 0.36 kg ⋅ m2.Part (a) Calculate the angular momentum, in kilogram meters squared per second, of the ice skater spinning at 6.2 rev/s. Part (b) He reduces his rate of rotation by extending his arms and increasing his moment of inertia. Find the value of his moment of inertia (in kilogram meters squared) if his rate of rotation decreases to 0.75 rev/s. Part (c) Suppose instead he keeps his...
4. An ice skater with rotational inertia I = 0.23 kg*m* is spinning with angular speed w. They pull their arms in, increasing their angular speed to 4w. What is the final moment of inertia?
If an ice skater has a rotational inertia of 100 kg*m^(2)while spinning with an angular velocity of 2 rad/s, what is the ice skaters angular velocity if she changes her rotational inertia to 50 kg*m^(2)?