If an ice skater has a rotational inertia of 100 kg*m^(2)while spinning with an angular velocity...
If an ice skater has a rotational inertia of 100 kg*m^(2)while spinning with an angular velocity of 2 rad/s, what is the ice skaters angular velocity if she changes her rotational inertia to 50 kg*m^(2)?
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If an ice skater has a rotational inertia of 100 kg*m^(2)while
spinning with an angular velocity...
4. An ice skater with rotational inertia I = 0.23 kg*m* is spinning with angular speed...
4. An ice skater with rotational inertia I = 0.23 kg*m* is spinning with angular speed w. They pull their arms in, increasing their angular speed to 4w. What is the final moment of inertia?
An ice- skater is initially spinning at an angular speed ω = 1.35 revolutions/s with a rotational inertia Ii = 2.30 kg.m...
An ice- skater is initially spinning at an angular speed ω = 1.35 revolutions/s with a rotational inertia Ii = 2.30 kg.m2 with her arms extended. When she pulls her arms in, her rotational inertia is reduced to If=1.05 kg.m2 . Assume no external torques act. a) Determine her initial angular speed in rad/s. (1 marks) b) Calculate her final angular speed in RPM (4 marks) c) Calculate the period of rotation when she is at her final speed (1...
An ice skater is spinning at a particular rotational velocity when she decides to bring her...
An ice skater is spinning at a particular rotational velocity when she decides to bring her arms inward, thus reducing her moment of inertia. If she reduces her moment of inertia by 20.0%, her rotational velocity will increase by what percent?
An ice skater is spinning at 2.5 revolutions per second and has a moment of inertia...
An ice skater is spinning at 2.5 revolutions per second and has a moment of inertia of 0.85 kg m2. Estimate her rotational angular momentum, assuming for simplicity that she can be approximated as a rigid, axially-symmetric body.
An ice skater with moment of inertia 70.0 kg•m2 is spinning at 41.0 rpm. If the...
An ice skater with moment of inertia 70.0 kg•m2 is spinning at 41.0 rpm. If the skater pulls in her arms, her moment of inertia decreases to 50.0 kg•m2. What is the skater’s resulting angular velocity?
An ice- skater is initially spinning at an angular speed ω = 1.35 revolutions/s with a...
An ice- skater is initially spinning at an angular speed ω = 1.35 revolutions/s with a rotational inertia Ii = 2.30 kg.m2 with her arms extended. When she pulls her arms in, her rotational inertia is reduced to If=1.05 kg.m2 . Assume no external torques act. a) Determine her initial angular speed in rad/s. (1 marks) b) Calculate her final angular speed in RPM (4 marks) c) Calculate the period of rotation when she is at her final speed (1...
Calculate the angular momentum, in kg · m2/s, of an ice skater spinning at 6.00 rev/s...
Calculate the angular momentum, in kg · m2/s, of an ice skater
spinning at 6.00 rev/s given his moment of inertia is 0.330 kg ·
m2.
(a) Calculate the angular momentum, in kg . m/s, of an ice skater spinning at 6.00 rev/s given his moment of inertia is 0.330 kg . m2. kg. m/s (b) He reduces his rate of spin (his angular velocity) by extending his arms and increasing his moment of inertia. Find the value of his...
An ice skater spinning with outstretched arms has an angular speed of 5.0rad/s . She tucks...
An ice skater spinning with outstretched arms has an angular speed of 5.0rad/s . She tucks in her arms, decreasing her moment of inertia by 29% . What is the resulting angular speed? rad/s By what factor does the skater's kinetic energy change? (Neglect any frictional effects.) where does the extra kinetic energy come from?
(a) Calculate the angular momentum (in kg-m/s) of an ice skater spinning at 6.00 rav/s given...
(a) Calculate the angular momentum (in kg-m/s) of an ice skater spinning at 6.00 rav/s given his moment of inertia is 0.470 kg m? kg-m/s (b) He reduces his rate of spin (his angular velocity) by extending wis arms and increasing his moment of inertia Find the value of his moment of inertia (in kg) ir his angular velocity drops to 2.05 rev/s. kgim² (c) Suppose instead he keeps his arms in and allows friction with the ice to slow...
A figure skater is spinning on frictionless ice. Treat the figure skater as a sphere with...
A figure skater is spinning on frictionless ice. Treat the figure skater as a sphere with radius R=.4m and mass M=60kg. The skater is holding onto a massless string attached to a weighted ball of m=10kg. The skater is initially spinning at an angular speed w0 of 2pi radians per second (1 rev/s) with a sting radius of r=1m. Moment of inertia for a sphere is I=(2/5)MR^2. 1.) What is the initial total rotational inertia of the skater and ball?...
4. An ice skater with rotational inertia I = 0.23 kg*m* is spinning with angular speed w. They pull their arms in, increasing their angular speed to 4w. What is the final moment of inertia?
Calculate the angular momentum, in kg · m2/s, of an ice skater
spinning at 6.00 rev/s given his moment of inertia is 0.330 kg ·
m2.
(a) Calculate the angular momentum, in kg . m/s, of an ice skater spinning at 6.00 rev/s given his moment of inertia is 0.330 kg . m2. kg. m/s (b) He reduces his rate of spin (his angular velocity) by extending his arms and increasing his moment of inertia. Find the value of his...
(a) Calculate the angular momentum (in kg-m/s) of an ice skater spinning at 6.00 rav/s given his moment of inertia is 0.470 kg m? kg-m/s (b) He reduces his rate of spin (his angular velocity) by extending wis arms and increasing his moment of inertia Find the value of his moment of inertia (in kg) ir his angular velocity drops to 2.05 rev/s. kgim² (c) Suppose instead he keeps his arms in and allows friction with the ice to slow...
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