An ice- skater is initially spinning at an angular speed ω = 1.35 revolutions/s with a rotational inertia Ii = 2.30 kg.m...
An ice- skater is initially spinning at an angular speed ω = 1.35 revolutions/s with a rotational inertia Ii = 2.30 kg.m2 with her arms extended. When she pulls her arms in, her rotational inertia is reduced to If=1.05 kg.m2 . Assume no external torques act.
a) Determine her initial angular speed in rad/s. (1 marks)
b) Calculate her final angular speed in RPM (4 marks)
c) Calculate the period of rotation when she is at her final speed (1 mark)
d) Prove that rotational kinetic energy was NOT conserved during the process. (3 marks)
e) Where did the extra rotational kinetic energy come from? (1 mark)
Homework Answers
Concept - use work energy theorem to find the work done to change the velocity as shown below,
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An ice- skater is initially spinning at an angular speed ω = 1.35 revolutions/s with a rotational inertia Ii = 2.30 kg.m...
An ice- skater is initially spinning at an angular speed ω = 1.35 revolutions/s with a...
An ice- skater is initially spinning at an angular speed ω = 1.35 revolutions/s with a rotational inertia Ii = 2.30 kg.m2 with her arms extended. When she pulls her arms in, her rotational inertia is reduced to If=1.05 kg.m2 . Assume no external torques act. a) Determine her initial angular speed in rad/s. (1 marks) b) Calculate her final angular speed in RPM (4 marks) c) Calculate the period of rotation when she is at her final speed (1...
4. An ice skater with rotational inertia I = 0.23 kg*m* is spinning with angular speed...
4. An ice skater with rotational inertia I = 0.23 kg*m* is spinning with angular speed w. They pull their arms in, increasing their angular speed to 4w. What is the final moment of inertia?
An ice skater spinning with outstretched arms has an angular speed of 5.0rad/s . She tucks...
An ice skater spinning with outstretched arms has an angular speed of 5.0rad/s . She tucks in her arms, decreasing her moment of inertia by 29% . What is the resulting angular speed? rad/s By what factor does the skater's kinetic energy change? (Neglect any frictional effects.) where does the extra kinetic energy come from?
An ice skater with moment of inertia 70.0 kg•m2 is spinning at 41.0 rpm. If the...
An ice skater with moment of inertia 70.0 kg•m2 is spinning at 41.0 rpm. If the skater pulls in her arms, her moment of inertia decreases to 50.0 kg•m2. What is the skater’s resulting angular velocity?
An ice skater is spinning at 2.5 revolutions per second and has a moment of inertia...
An ice skater is spinning at 2.5 revolutions per second and has a moment of inertia of 0.85 kg m2. Estimate her rotational angular momentum, assuming for simplicity that she can be approximated as a rigid, axially-symmetric body.
If an ice skater has a rotational inertia of 100 kg*m^(2)while spinning with an angular velocity...
If an ice skater has a rotational inertia of 100 kg*m^(2)while spinning with an angular velocity of 2 rad/s, what is the ice skaters angular velocity if she changes her rotational inertia to 50 kg*m^(2)?
A 60.0-kg skater begins a spin with an angular speed of 6.0 rad/s and of moment...
A 60.0-kg skater begins a spin with an angular speed of 6.0 rad/s and of moment of inertia 3.0 kg.m2. By changing the position of her arms, the skater decreases her moment of inertia to one-half its initial value. What is the skater's initial kinetic energy?
(a) Calculate the angular momentum (in kg.m"/s) of an ice skater spinning at 6.00 rev/s given...
(a) Calculate the angular momentum (in kg.m"/s) of an ice skater spinning at 6.00 rev/s given his moment of inertia is 0.470 kg-m kg-m /s (b) He reduces his rate of spin (his angular velocity) by extending his arms and increasing his moment of inertia. Find the value of his moment of inertia (in kg-m2) if his angular velocity drops to 1.35 rev/s. (c) Suppose instead he keeps his arms in and allows friction with the ice to slow him...
Problem 2. An ice skater is spinning at 60 RPM (counter-clockwise) when she pulls in her...
Problem 2. An ice skater is spinning at 60 RPM (counter-clockwise) when she pulls in her arms and undergoes an angular acceleration of 10 rad/s' for 0.6 seconds. What was her final RPM and how many rotations did she spin during this time?
Question 8 (6 points) A 60.0-kg skater is spinning at 0.800 rev/s with her arms and...
Question 8 (6 points) A 60.0-kg skater is spinning at 0.800 rev/s with her arms and legs extended outward. In this position her moment of inertia with respect to the vertical axis about which she is spinning is 6.00 kg•m?. She pulls her arms and legs in close to her body changing her moment of inertia to 2.00 kg•m². What is her final angular velocity in rad/s? a) 8.71 rad/s b) 15.1 rad/s c) 2.40 rad/s d) 0.800 rad/s e)...
4. An ice skater with rotational inertia I = 0.23 kg*m* is spinning with angular speed w. They pull their arms in, increasing their angular speed to 4w. What is the final moment of inertia?
(a) Calculate the angular momentum (in kg.m"/s) of an ice skater spinning at 6.00 rev/s given his moment of inertia is 0.470 kg-m kg-m /s (b) He reduces his rate of spin (his angular velocity) by extending his arms and increasing his moment of inertia. Find the value of his moment of inertia (in kg-m2) if his angular velocity drops to 1.35 rev/s. (c) Suppose instead he keeps his arms in and allows friction with the ice to slow him...
Problem 2. An ice skater is spinning at 60 RPM (counter-clockwise) when she pulls in her arms and undergoes an angular acceleration of 10 rad/s' for 0.6 seconds. What was her final RPM and how many rotations did she spin during this time?
Question 8 (6 points) A 60.0-kg skater is spinning at 0.800 rev/s with her arms and legs extended outward. In this position her moment of inertia with respect to the vertical axis about which she is spinning is 6.00 kg•m?. She pulls her arms and legs in close to her body changing her moment of inertia to 2.00 kg•m². What is her final angular velocity in rad/s? a) 8.71 rad/s b) 15.1 rad/s c) 2.40 rad/s d) 0.800 rad/s e)...
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