Problem 2. An ice skater is spinning at 60 RPM (counter-clockwise) when she pulls in her...

Question

Question

Problem 2. An ice skater is spinning at 60 RPM (counter-clockwise) when she pulls in her arms and undergoes an angular accele

Answer 1

Answer #1

(a) w=w0+a*t
w0= 60 rpm = 60*2*pi/60 = 2*pi rad/s
w= 6.28 + 10*0.6

w=6.28 + 6
w= 12.28 rad/s

round In 1 s =>12.28/ 2pi

So,

In 60 s => (12.28 / 2 pi)*60 RPM

=117.26 RPM

*(1 RPM is 0.104719755 rad /s)

s= 0.5*a*t^2 + wo*t
s=(0.5*10*0.6^2) + (6.28*0.6)

s=1.8 + 3.768
s=5.568 radians = 0.89 rotation

I hope help you !!

Answer 2

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