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Company XYZ know that replacement times for the quartz time pieces it produces are normally distributed...

Company XYZ know that replacement times for the quartz time pieces it produces are normally distributed with a mean of 13.7 years and a standard deviation of 0.8 years.

Find the probability that a randomly selected quartz time piece will have a replacement time less than 11.8 years?
P(X < 11.8 years) =

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Answer #1

X ~ N ( µ = 13.7 , σ = 0.8 )
P ( X < 11.8 )
Standardizing the value
Z = ( X - µ ) / σ
Z = ( 11.8 - 13.7 ) / 0.8
Z = -2.375
P ( ( X - µ ) / σ ) < ( 11.8 - 13.7 ) / 0.8 )
P ( X < 11.8 ) = P ( Z < -2.375 )
P ( X < 11.8 ) = 0.0088


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