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5 4-19 points BBUnderStat12 7.1.024. G My Notes Ask Your Teacher Jobs and productivity! How do retail stores rate? One way to
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Answer #1

We have,

sample size: n = 35

Population standard deviation: o =4

a) Mean of data set: (using Excel average function)

T = 5.068571429 5.07 thousand dollars per employee

b) 80% confidence interval

Confidence level: c = 0.8

Level of significance:

a=1-0.8 = 0.2

LO=

Find corresponding z score:

29 = 20.1 = 1.28

Confidence interval formula:

CI = 7 土々*

Plugging in all values we get,

CI = 5.07 – 1.28 * 32

\Rightarrow CI=5.07\pm0.8654

→ CI = (4.2046,5.9354) (4.20,5.94)

Lower limit: 4.20 thousand dollars

Upper limit: 5.94 thousand dollars

c) At 80% of confidence level average profit per employee lies within 4.20 thousand dollars to 5.94 thousand dollars. 3 thousand dollars is far less than the lower limit of confidence interval.

Hence this confidence interval suggest that the profits per employee are less than those of other retail stores.

Yes. This confidence interval suggest that the profits per employee are less than those of other retail stores.

d) At 80% of confidence level average profit per employee lies within 4.20 thousand dollars to 5.94 thousand dollars. 6.5 thousand dollars is far above than the upper limit of confidence interval.

Hence this confidence interval suggest that the profits per employee are greater than those of other retail stores.

Hence yes as a store manager I will feel better.

Yes. This confidence interval suggest that the profits per employee are greater than those of other retail stores.

e) 95% confidence interval

Confidence level: c = 0.95

Level of significance:

a=1-0.95 = 0.05

= = 0.025

Find corresponding z score:

29 = 20.025 = 1.96

Confidence interval formula:

CI = 7 土々*

Plugging in all values we get,

CI = 5.07 1.96 *

CI = 5.07 +1.3252

CI = (3.7448, 6.3952) (3.74, 6.4)

Lower limit: 3.74 thousand dollars

Upper limit: 6.4 thousand dollars

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