22) Using,
log(K2) - log(K1) = E/2.303R [1/T1 - 1/T2]
log(K2) - log(3.45×10-2) = 145000/2.303×8.314 [1/283 - 1/303]
log(K2) + 1.462 = 7572.93 [0.003335 - 0.003300]
log(K2) = 7572.93×0.000035 - 1.462
log(K2) = -1.1969
K2 = 10-1.1969 = 0.06355 = 6.35×10-2 M-1 s-1
23) a) Yes. Intermediate is HOI and OH-
b) No.
c) Net reaction :
HOOH + 2I- + 2H3O+ -> I 2 + 4H2O
please help with question 22 and 23. showing all work 22. (Apts) A given reaction has...
(References) This question has multiple parts. Work all the parts to get the most points. The reaction 2NO() + 2H2(g) → N (9) + 2H20(9) was studied at 904°C, and the data in the table were collected, Reaction Rate of Trial Concentration Appearance of Ne (mol/L) (mol/L-s) [NO] [H.] 1 0.420 0.122 0.136 2 0.210 0.122 0.0339 3 0.210 0.244 0.0678 4 0.106 0.488 0.0339 a which two reaction trials can be used to determine the order of the reaction...