the stoichiometric ratio of H3PO4 g/mol NaOH
the stoichiometric ratio of H3PO4 g/mol NaOH Suppose a similar experiment had been done using 1.0...
Suppose a student performed a similar standardization titration experiment using the data in the table here. What is the exact concentration of the NaOH solution? The molar mass of benzoic acid is 122.12 g/mol.
when .0015 M of HCl reacts with .0035 M NaOH.
how do I get HCl as the limiting reactant?
HC # Results/Observations 1 Reaction Between Hydrochloric Acid and Sodium Hydroxide Table 1 ml LOM mol HCI ml 1.0M mol NaOH Temperature NaOHT change. "C 19. 10 0045 50L2012 .0005 22.4 #2 19.10.0 .004 10.09.11 .001 24.3 #3 1949350 -0035 15.020 Ốc DD15 265 #499 300 003 20.0 20.10 .002 27.3 #5 A5 2.0 .0025 25.0 20. 0 0025 2100 #6...
given From H2S a but the same 2. If a third set of reactions was done using 1.0 MH,PO, and 1.0 M KOH solutions, what would the graph look like and what would the stoichiometric molar ratio be for H,PO and KOH? Why? Moles of acid 0.60 0.40 1.00 0.80 0.20 0.00 16 0.00 0.20 0.80 1.00 0.40 0.60 Moles of base 3. Suppose that another trial of this experiment produced the graph above. If the acid is known to...
Suppose you performed a similar experiment using an unknown sample of carbonate. The pressure and volume were measured after the temperature stabilized at 21.5 ºC. Given the data in the table below, what is the stoichiometric ratio between HCl and CO2? initial pressure (atm) 1.00 initial gas volume (mL) 240.0 volume of 1.00 M HCl solution added to fully consume the carbonate sample (mL) 22.0 final pressure (atm) 2.32 final gas volume (mL) 218.0
culate the molarity (M) of an unknown solution of hydrochlorie acid (HCT). This experiment similar to the one as done in the lab session.. The acid solution was titrated in a flask with a solution of NaOH added from the buret until the end point (light pink color in the flask) was seen. Followings are the data measured by a student. (3 points) Molarity (M) of NaOH (given) Volume of acid ( measured) in the flask Volume of NaOH required...
Suppose 1.00 g of NaOH is used to prepare 250 mL of an NaOH solution. Compare the expected molarity of this solution to the actual average molarity you measured in the standardization. What do you notice? Do you think the results would have been more accurate if a different type of acid or base were used in the standardization? Why, or why not? There are many different primary standards that could be used in a standardization titration. What are the...
If this experiment had been performed using the compound 2,5-dimethylcyclohexan-3-ol in the presence of catalytic amounts of concentrated sulfuric acid, what products would you expect to find in the distillate? Draw the chemical reaction and include all the structures of the products you expect. Underline the major product.
E AFTER COMPLETING LAB. ANSWER IN SPACE PROVIDED. Suppose the heat of neutralization had been determined using a glass beaker instead of a polystyrene coffee cup How would the measured value have been affected? The heat of combustion of octane, C,H,. can be measured in a way similar to the method youC used to measure the heat of neutralization. The bomb calorimeter is used instead of a coffee cup. The reaction is 2C,H,1)+ 25 O, (g) 16 CO, (g) +...
Your ticket will appear here once you na ve correctly ans w ered an or ше реао quesuon. Prelab for Experiment 6- Titration of an Unknown Acid In this prelab, answers to questions l and 2 should be reported toateastisennoantngurs Scientific notation format 2.34E 4. The 'E' must be capitalized." The prelab questions mirror those that you will be doing at the end of the experiment. Bring your work for this prelab assignment to lab and you will have a...
Say for example, that you had prepared a Buffer C, in which you mixed 8.203 g of sodium acetate,NaC2H3O2, with 100.0 mL of 1.0 M acetic acid. 1A. What would be the initial pH of Buffer C 1B. If you add 5.0 mL of 0.5 M NaOH solution to 20.0 mL each of Buffer B( initial pH of Buffer B is 3.83), and Buffer C, Which buffer's pH would change less? Explain