Question

Can someone please help me solve these, please show work/explanation and answer!

8. A 7.8 g sample of CsHNH3Cl is dissolved in water to make 350 mL of solution. What is the pH of the solution? Numbers 9-14 are predominant species problems! Explain your answer. 9. Which of the following best describes the composition of a solution labeled "0.10 M H2SO4"? a. [H2SO4) = 0.10 M b. [H+] > 0.10 M, (S0221 = 0.10 M C. [H+] = 0.20 M, [SO42] = 0.10 M d. [H+] > 0.10 M, (HSO4] <0.10 M e. [H] = 0.10 M, [HSO4) = 0.10 M 10. Which of the following best describes the composition of a solution labeled "0,10 M HCI"? a. (HCl) = 0.10 M b. [H] <0.10 M, [Cl] < 0.10 M C. [H'] = 0.10 M, [Cl] = 0.10 M

Answer 1

7.8gm of CSHENUzel = 1,8 g = 0.066 mole There CGHE NHzel is dissolved in water make = 350 mi. 12 = 103 mL that use the fact you dissolved 0.066 mole.. To do that - 103 mi solution & 0.066 mole C5 Ha Ndsel. 350 me solution thote = 0·10857 mole CGHE NH3el. . As we know, the pH of the solution is calculated by usind the equation. PH = -log ( [0.184577) = 0.72 2. # o "0.10 M His Oy" tere lom H₂SO4 = molar mass x mole =gEX0.10=9.8 g from opzion (2), 2H+] = -20m [soy² = 0.1m H₂sou sou? 0.1 = g.8 g [.h here 2] so option (6) is correct answere. 10 composition debeled wo im Hel" Here at el a both are one mole. we ean say option () is correct Answere Ll+] = 0.10m, [el] = 0.1om. 22*0.10 = 2,