Use the following chemical equation to answer questions 11-15. Na3PO4 + 3AgNO3 → Ag3PO4 + 3NaNO3...

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Question

Answer 1

Answer #1

Moles of AgNO₃ = mass / molar mass = 35 / (108 + 14 + 3 * 16) = 0.206 moles

From the equation: moles of Ag₃PO₄ = 1/3 * moles of AgNO₃ = 1/3 * 0.206 = 0.069 moles

Mass of Ag₃PO₄ = mole * molar mass = 0.069 * (108*3 + 31 + 4 * 16) = 28.91 g

Answer 2

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