What will be the pH value when we add 10 mL of 2 molar NaOH solution...
What will be the pH value when we add 10 mL of 2 molar NaOH solution to 1 litre of 0.2 molar acetate buffer whose pH is 4.7? Pka = 4.7
Homework Answers
pH of acidic buffer = pka +
log(ch3cooNa/CH33COOH)
pka of CH3COOH = -logKa = 4.74
Total no of mol of buffer = 0.2*1 = 0.2 mole
no of mol of CH3COOH = x mole
No of mol of CH3COONa = NaOH = 0.2- x mole
4.74 = 4.74+log((0.2-x)/x)
x = 0.1
no of mol of CH3COOH = x = 0.1 mole
No of mol of CH3COONa = NaOH = 0.2- 0.1 = 0.1 mole
No of mol of NaOH added = 10*2*10^-3 = 0.02 mole
pH = pka + log((CH3COONa+NaOH/CH3COOH-NaOH)
= 4.74 + log((0.1+0.02)/(0.1-0.02))
pH = 4.92
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