Question

< Question 8 of 13 > A sample of an ideal gas has a volume of 3.10 L at 13.20 °C and 1.90 atm. What is the volume of the gas at 20.80'C and 0.994 atm?

Answer 1

According to the combinea gas law we know that PiVI P2V2 T2 Hene, P, ana v are pressure and volume at Ti temperatune. P2 anava are pressure and volume respectively at Ta temparatone. 1. Accroding to the question; P = 1.90 atm P2 = 0.094 atm Vi= 3.10L V2 = ? from equation (1) T = 13.20°c = 286 20K T2 = 20.80°C = 293.80K PIVI - Prz TI => 1.00% 3.10 0.99AX V2 286. 20 293.80 1.90x3.10 x 293.80 V2 = 0.994 x 286-20 - 6.083L of the ideal gas is 6.0832 i volume

2. According to the question; P = 1.02 afm P2 = ? V = 2.272 v2 = 1.27L Ti= 2.9x102K P. T2 = 306k from the equation 1 PIVI = P2 V 2 TIT => 1.0282.27 - P2X127 2.96102 - 306 = P = 10282.278306 2.9x102x1.27 = P2 = 1.923 atm. atm for this pressure is 1923 ideal gas.