Bonus Question. 54.00 mL of a 0.25 M NaOH nolution in titrated with 0.10M HCL What...

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Answer 1

Answer #1

NaOHT Hel nacl t H₂o Moly of Noon, 0.25x S4 mnd - 13.5 mmol moles of HU 0.10 x 29 mart & 2.9 mil Moly of Naoh remaining 13.5

Answer 2

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