Question

1. If 40.00 mL of 0.050 M HCl is titrated with 0.100 M NaOH, what is the pH at the following "times?" (9 pts) a. Before any NaOH is added. b. After 20.00 mL of NaOH is added. c. After 500 mL of NaOH is added. 2. If 50.00 mL of 0.050 M formic acid, HCHO, (yes, you need to look up the Ka for formic acid) is titrated with 0.050 M NaOH, what is the pH at the following "times?" (12 pts) a. Before any NaOH is added. b. After 25.00 mL of NaOH is added. c. After 50.00 mL of NaOH is added. d. After 100.00 mL of NaOH is added. 3. If the Ksp for CaCO3(s) is 8.7*10“, how many grams (MM = 100.0 g/mole) will be soluble in 336.8 L? (2 pts)

Answer 1

D Given's ruce NaOH 40mL O.IM 0,05M solution :- @ He. 0,05M YomL na of neotes ИС Httce- 0,05M 0.05M [ht] = 0.05MI pH = -log[ht] = -log(0.05) pH = 1:30) (6 Hu NaOH 40mL OM 0.05M gomL no. of milli nf XMXV gram n Ex Mxv to nexuXV equivalents a = 1x40 XO OS 1x0.1820 2 Hence a moram equivalents of the will be neutralised by 2 milligram equivalents of Naoh completely. So pH will be 7 O Hee 40mL no. of milli 0,05M grath nexMV 1xo.OsxYO NaOH | 0 , M. SoomL nf XMxv Ixo, 1x500 50 ho of milli 48

& [oH) - 4 8 156) 540 pOH = -log[on]e -log(e) = 1,013 pH e 14-00H 14 – 1.018 - 12.982 pH = 12,982)