A student titrated a 100.0 mL sample of 0.100 M acetic acid with 0.050 M NaOH. (For acetic acid, Ka = 1.8 * 10^-5 at this temperature.)
(a) Calculate the initial pH.
(b) Calculate the pH after 50.0 mL of NaOH has been added.
(c) Determine the volume of added base required to reach the equivalence point.
(d) Determine the pH at the equivalence point?
A student titrated a 100.0 mL sample of 0.100 M acetic acid with 0.050 M NaOH....
40.0 ml of an acetic acid of unknown concentration is titrated with 0.100 M NaOH. After 20.0 mL of the base solution has been added, the pH in the titration flask is 5.10. What was the concentration of the original acetic acid solution? [Ka(CH3COOH) = 1.8 × 10–5]
Consider the titration of the titration of 50.0 mL of 0.100 M acetic acid (HC2H2O2) with 0.100 M. The pka = 4.76. d. Determine the pH after 50.0 mL of titrant (NaOH) have been added. This is the equivalence point. All of the acid has been converted to its conjugate base, pH is determined by the equilibrium for the conjugate base
50.0 mL of 0.090 M nitrous acid (HNO2, Ka = 7.1 x 10-4), is titrated with 0.100 M NaOH, requiring 45.0 mL of strong base to reach the equivalence point. (a) What will be the pH after 35.0 mL of NaOH have been added? (b) What will be the pH at the equivalence point? (c) What will be the pH after 60.0 mL of NaOH have been added?
1. If 40.00 mL of 0.050 M HCl is titrated with 0.100 M NaOH, what is the pH at the following "times?" (9 pts) a. Before any NaOH is added. b. After 20.00 mL of NaOH is added. c. After 500 mL of NaOH is added. 2. If 50.00 mL of 0.050 M formic acid, HCHO, (yes, you need to look up the Ka for formic acid) is titrated with 0.050 M NaOH, what is the pH at the following...
What is the pH of a solution of 40.0 mL of 0.100 M acetic acid (Ka = 1.8 x 10-5) after 50.0 mL of 0.100 M NaOH has been added? Calculate the concentration of dissolved Ba2+ ions when BaSO4 is added to water at 25°C. Кsp? = 1.10 x 10-10 A particular saturated solution of silver chromate (Ag2CrO4), has [Ag+] = 5.0 x 10 Mand (CrO4) = 4.4 x 10M. What is value Ksp for silver chromate? As a result...
A 50.0 ml sample of 0.50 M acetic acid, ch3cooh is titrated with a 0.150 M NaOH solution. calculate the ph after 25.0 ml of the base have been added (ka=1.8x10^-5)
A sample of 0.100 M acetic acid (Ka = 1.8 × 10−5) in 50.0 mL of solution is titrated with standard 0.100 M NaOH. What is the pH in the titration flask after addition of 15.0 mL of NaOH?
Calculate the pH of a solution when 100.0 mL of a 0.100 M solution of acetic acid (CH3COOH), which has a Ka value of 1.8 × 10–5, is titrated with 110 mLs of a 0.10 M NaOH solution.
You are provided with 100 mL of 0.100 M acetic acid (CH3COOH, Ka = 1.8 x 10-5), which you will be asked to titrate with 0.050 M sodium hydroxide (NaOH). (a) What is the pH after the addition of 80 mL of the 0.050 M sodium hydroxide solution? Show your work. In your answer, show the reaction that occurs when the sodium hydroxide is added. (b) What is the pH at of the solution at the equivalence point (where the...
A volume of 50.0 mL of 0.100 M CH3COOH(aq) is titrated with 0.100 M NaOH(aq). What is the pH at the equivalence point? (Ka for CH3COOH = 1.8 × 10–5) (1) 7 (2) 5.28 (3) 8.72 (4) 6.34 (5) 4.15