Question

Assume that a 50.00 mL sample of 0.1000 M HCl in an Erlenmeyer flask is titrated with 0.1000 M NaOH. (a) What is the initial pH before any base is added? (6) What is the pH of the solution after 10.00 mL of NaOH? (c) What is the pH of the solution after 20.00 mL of NaOH? (d) What is the pH of the solution after 50.00 mL of NaOH? (e) What is the pH of the solution after 60.00 mL of NaOH?

Answer 1

[ht] = 0.066M pH = -logo.066 = 1.18M C) After 20 mL of Nach is added THI - SOMLXO.im - 20 mLXO. Im 70mL = 0.04285TM -1090.042857 = 18368 PP D) After some of NaoH is added THt] - Somixo.1 - some xo. im =o 100 mL . All the 4t is consumed o only it from dissociation of water is left in the solution At from dissociation of water = 10 m

ni pH-109[ht] = -1091ő? =) e) 60 mL NaOH is added in Oh will be left equivalence point solution beyond the [OH-] = 60 mL Xol-some xool 110mL 0.00909 poll - – 609[OH-] = -logo.00909 pol = 2.04 ) PH=14-POH pH = 14-2.04 = 11.96