Question

the reaction of 5.00g of copper (ll) and 5.00g potassium phosphate. what is the limiting and excess reactant? what is the yeild of your solid in grams?

Answer 1

The reaction is 3 cut? + 2 kg pou cualpoudacest 6kh marlau mass of culi) = 63.5 gimol mole of sg of culll) = 5 g = 0.0787 mal 63.5 gimul - or malu mass of kz pou = 212 glmal make of Sg og k3p0u = 59 ml = 0.0235 meel 212 g/mol K₃ Pou 3 mol of Cully react with 2 mace of K₂ PO4 0.0187 mcal of Culli) react with = ?X0.0787 mole of - О-o524 mole Kз "o, region. But K₂ pou moles are a. o 235 mole this kapou it limiting reagent and Cucal) is in excess. as a mole of kz pou give 1 mole of Cl2 (PO4). sung 0.0235 mole of Kapoy give 0.0235 mole of (uz (pouz = 0.01175 mole of Luz CPOud, poodile molar mass of Cuz CPO4)2 = 380.5 glmal mass of Cuz e pour produced = 380.5*0.011759 4.4.7 g f (03 CPOudz this field of solid poodice = 4.479. 2- TYNYT