help with the following show all work!
Answer is 1.76mM . I keep on getting 2.3 Show all work please!
Homework Answers
Given data,
[Mg2+] = 0.0500 M
Ksp of MgF2 = 8.4 x 10-8
Let us consider a reaction,
MgF2 <-------------> Mg2+ + 2F-
Ksp = [Mg2+] [F-]2
Ksp = [s] [2s]2
Ksp = [s+ 0.050] [2s]2
8.4 × 10–8 = [s+ 0.050 ] [4s2]
8.4 × 10–8 = 4s3 + 0.2 s2
Since s is very small, s3 can be neglected.
Hence,
8.4 × 10–8 = 0.2 s2
s2 = 4.2 × 10–7
= 0.000648
= 6.48 x 10-4 M
Therefore, the molar solubility = 6.48 x 10-4 M
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help with the following show all work!
Answer is 1.76mM . I keep on getting 2.3...
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than the activity method is wrong. kindly explain. thanks
the ksp is 1.8 ×10^-10
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