Homework Answers
a) The expression of heat absorbed by water and released by metal is related:
m * cp * ΔT water = - m * cp * ΔT metal
180 * 4.18 * (Tf - 5) = - 55 * 0.694 * (Tf - 305)
Tf = 19.5 ° C is cleared
b) You have:
120 * 4.18 * (24.3 - 21) = - m * 0.649 * (24.3 - 200)
It clears m = 14.5 g
c) The required heat is calculated:
q = 0.18 * 32.1 * 0.71 * (-24.5 - 18) = - 174.4 J
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average specific heat = 0.694 J/g degres celcius
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similar.
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