Single Sample t-Test:
Ho : Population is symmetric about zero i.e. mean(μ)= 0
Ha : Population is not symmetric about zero i.e. mean(μ) != 0
Sample: 6, -2, 4 ; n = 3
x̅ = [ 6 + (-2) + 4 ] / 3
Sample mean (x̅) = 2.667
Sample Standard Deviation (s) = 4.163
t = (2.667 - 0) / (4.163/√3)
t = 1.109
df = n-1 = 2
p-value = P(t > 1.109) + P(t < -1.109) @ df = 2 and 95% confidence interval
The P-Value is 0.382925.
The result is not significant at p <
0.05
=> It null hypothesis(Ho) can not rejected, means Population is symmetric about zero
Permutation Test:
a. Permutation of sample : Problem is similar to tossing 3 coins simultaneously and outcomes are 8 (HHH,HHT,HTT.......TTT)
b. ample: (6, 2, 4), (6, 2, -4), (6, -2, 4), (-6, 2, 4), (6, -2,- 4), (-6, 2, -4), (-6, -2, 4), (-6, -2, -4)
Sample Average: 4, 1.333, 2.667, 0, 0, -2.667, -1.333, -4
c. -4, -2.667, -1.333, 0, 0, 1.333, 2.667, 4
d.
Ho : All means are equal i.e. mean(μ1= μ2 = μ3.......=μ8)= 0
Ha : At least two means are not equal
P-value = 0.386 > alpha(0.05)
Hence Ho is not rejected i.e Population means are equal
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