Question

In a normally distributed data set of how long customers stay in your store, the mean...

In a normally distributed data set of how long customers stay in your store, the mean is 44.8 minutes and the standard deviation is 2.6 minutes. Within what range would you expect 95% of your customers to stay in your store?

a2.6-44.8

b37.0-52.6

c42.2-47.4

d39.6-50.0

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Here,

X ~ Normal(44.8, 2.62)

To find x_1 and x_2 such that

P(2.1 < X < .r2) = 0.95

) = 0.95 2,6 2.6 2.6

T1-44.8 P( KZ = 0.95 2.6

P(Z 22-44.8 2.6 )-P(Z-L 44.8 = 0.95

44.8 )-Ф( -2.0 T1-44.8 ) = 0.95

2 44.8 2.6 21-14.8 2.6 Ф( D( ) = 0.975-0.025

One solution may be

2 44.8 2.6 Ф( ) 0.975 and 44.8) 0,025 Ф(

Now,

2 44.8 2.6 Ф( ) 0.975

2 44.8 2.6 = Φ-1 (0.975) 1.95996

244.8(1.95996 2.6)

72 = 49.8959

and

44.8) 0,025 Ф(

Rightarrow rac{x_1-44.8}{2.6}= Phi^{-1}(0.025) = -1.95996

2.1 = 44.8-(1.95996 * 2.6)

1 39.7041

ans-> d) 39.6 - 50.0

Add a comment
Know the answer?
Add Answer to:
In a normally distributed data set of how long customers stay in your store, the mean...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT