(CO 1) In a normally distributed data set of how long customers stay in your store, the mean is 44.8 minutes and the standard deviation is 2.6 minutes. Within what range would you expect 95% of your customers to stay in your store?
For confidence interval we have,
Lower limit : u - z*
Upper limit : u + z*
Here,
u = mean = 44.8
= std deviation
= 2.6
z = 95% confidence interval z score = 1.96
Thus,
Lower limit : 44.8 - 1.96*2.6 = 39.70
Upper limit : 44.8 + 1.96*2.6 = 48.90
Thus, 95% of your customers to stay in your store within (39.7, 49.9)
(CO 1) In a normally distributed data set of how long customers stay in your store,...
In a normally distributed data set of how long customers stay in your store, the mean is 44.8 minutes and the standard deviation is 2.6 minutes. Within what range would you expect 95% of your customers to stay in your store? a2.6-44.8 b37.0-52.6 c42.2-47.4 d39.6-50.0
(CO 1) In a normally distributed data set of how long customers stay in your store, the mean is 50.3 minutes and the standard deviation is 3.6 minutes. Within what range would you expect 95% of your customers to stay in your store 39.5-61.1 46.7-53.9 43.1-57.5 48.5-52.1
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