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A 15.0 mL sample of 0.21 M HNO3 is titrated with 0.15 M LiOH. Calculate the pH after the addition of the following volumes of

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Answer:-

This question is solved by using the simple concept of reaction of strong acid and strong base and their pH at different intervals.

The answer is given in the image,

Anul: CHN0,7 = 0.21M, CLIC] = 015M @ HHQ + HoHo LiNO3 + H20 O-DOM 0407)= (HNO3)=0.217 PMS-Leg (Hofj= -log(0-21) PH = 0.68 . 1

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