A 28.8 g piece of iron and a 20.7 g piece of gold at 100.0°C were dropped into 630.0 mL of water at 19.0°C. The molar heat capacities of iron and gold are 25.19 J/(mol·°C) and 25.41 J/(mol·°C), respectively.
What is the final temperature of the water and pieces of metal?
A 28.8 g piece of iron and a 20.7 g piece of gold at 100.0°C were...
A 24.65 apiece of iron and a 20.60 g piece of gold at 100.0 degree C were dropped into 770.0 mL of water at 21.70 degree C. The molar heat capacities of iron and gold are 25.19 J/(mol degree C) and 25.41 J/(mol, degree C), respectively. What is the final temperature of the water and pieces of metal?
Calculate ΔΗ for the reaction C(s)HO(g) co, given the following: - C(s) +02(g) CO(g) ΔΗ-65.85 kJ 15 pts 5. BONUS QUESTION .+10 PTS.. directly from Smartsork Homework 3) A 23.40 g piece of iron and a 20.95 g piece of gold at 100°C were dropped into 790.0 ml. of water (density- 1.00 g/mL) at 19.50°C. The molar heat capacities of iron and gold are 25.19 J/(mol.'C) and 25.41 J/(mol.°C), respectively, and the specific heat of water is 4.184 J/(g. C)....
A piece of metal weighing 60.922 g was heated to 100.0°C and then put into 100.0 mL of water (initially at 23.7°C). The metal and water were allowed to come to equilibrium temperature, determined to be 27.8°C. A) What is the specific heat of the metal? [ Select ] B) Was the reaction endothermic or exothermic? For the water... [ Select ] For the metal... [ Select ] C) What is the identity of the metal? [ Select ] Aluminum...
5) If 78.6 g piece of iron is dropped into 100.0 g of water initially at 24.6 °C. The final temperature of both water and iron was measure at 28.5 °C. Calculate the initial temperature of iron? (Specific heat of water and iron from #1)
Exactly 10.3 mL of water at 29.0°C is added to a hot iron skillet. All of the water is converted into steam at 100.0°C. The mass of the pan is 1.30 kg and the molar heat capacity of iron is 25.19 J/mol C). What is the temperature change of the skillet? oC Exactly 10.3 mL of water at 29.0°C is added to a hot iron skillet. All of the water is converted into steam at 100.0°C. The mass of the...
Exactly 17.8 mL of water at 28.0 °C is added to a hot iron skillet. All of the water is converted into steam at 100.0°C. The mass of the pan is 1.45 kg and the molar heat capacity of iron is 25.19 J/(mol·°C). What is the temperature change of the skillet?
A piece of titanium at 100.0°C was dropped into 50.0 g of water at 20.0°C. The final temperature of the system was 22.6°C. What was the mass of the titanium? Specific heat (J/g°C) titanium 0.54 water 4.184
A piece of metal of mass 35.0 g at 100.0°C was placed in 150.0 g of water at 20.0 °C. After stirring, the final temperature of the water and the metal is 23.8°C. What is the specific heat capacity of the metal? (specific heat capacity for H2O = 4.184 J/g °C) O-0.89 J 8°C 19.6 J/g °C 1.96J/g °C O 0.89 J/g °C
A 296.0 g piece of granite, heated to 601.0°C in a campfire, is dropped into 1.10 L water (d = 1.00 g/mL) at 25.0°C. The molar heat capacity of water is cp,water = 75.3 J/(mol ·°C), and the specific heat of granite is cs,granite = 0.790 J/(g ·°C). Calculate the final temperature of the granite.
A 301.0 g piece of granite, heated to 561.0°C in a campfire, is dropped into 1.00 L water (d = 1.00 g/mL) at 25.0°C. The molar heat capacity of water is cp,water = 75.3 J/(mol ·°C), and the specific heat of granite is cs,granite = 0.790 J/(g ·°C). Calculate the final temperature of the granite.