Given that,
Ksp = 9.14*10^-9
C2D3 -----> 2C3+ + 3D2-
2s 3s (at equilibrium)
Where s is the molar solubility.
Ksp = [C3+]^2 [D2-]^3
9.14*10^-9 = (2s)^2 * (3s)^3
9.14*10^-9 = 4s^2 * 27s^3
9.14*10^-9 = 108 * s^5
s = 0.00967 mol/liter or M OR 9.67*10^-3 M ....Answer
Let me know if any doubts.
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C2D3 has a solubility product constant of 9.14 x 10^-9. What is the molar solubilty of C2D3?
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