Question

A pin-code consist of 3 numbers. We know that the second digit is not a 5 and the third digit is not 3 or 4. How many possible arrgements correspond to such pin-code? 5.

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Answer #1

here for first digit there are 10 choices of an integer ; for second digit there are 9 choices except a 5 and for third digit there are 8 choices except 3 or 4;

hence number of possible arrangements =10*9*8=720

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