Question

Part D K, for hypochlorous acid, HCIO, is 3.0x108. Calculate the pH after 10.0 mL of 0.100 M NaOH have been added to 40.0 mL of 0.100 M HCIO. O AQ O O ? Submit Request Answer

Answer 1

Equilibrium :- Hero + NaOH Ka Na Ool + H₂O+H* acid base Salt ce equilibriun equation can be written as ka= [H] [ Nau) [Hud] A. . [ht] = Ka Phao] - [Nou] : -log[ht] - - Logika fheld [Taking - logie in both side] TNaou] | Ka=3x108 Plonitial concentration of HU-40 mL - O.IM Plnitial concentration of 1000 mL IM HUD NaOH = 10 mb - 0.1M Nabi Imel HUO - 40mL DIM HU07 40x01, 4810-3 mol HUO pH = -logka - inz Habers PH = PK - Le 2 1000 mL IM Naoth of Imol Nadh to mL or Nath & loxor - 10-3 mol Nadh 1000 1 mol of Nadh will produce I and of Nale . 10-3 mol of ni.. u 103 mol i Total volume of the solutions 10+40-50 mL . 1000 ml 1 mol NaOU IM NADU 50 ml 10-3 mol Naoce a 50x103 M.2 0.05m. Remaining Hud- Textos_103) 3810-3 mol : (HCl) - 50x3x10-3= 0.15 M. plas-log[3x10-9-7.52 pH = trek 7.52 – long co.us = 7:52 - log 3 7.59-0.477 - 7.04 1pH=7.04