S K, for hypochlorous acid, HCIO, is 3.0x10-8. Calculate the pH after 16.6.20.0.30.6, and 40.0 mL...
Part E K, for hypochlorous acid, HCIO, is 3.0x10-8. Calculate the pH after 20.0 mL of 0.100 M NaOH have been added to 40.0 mL of 0.100 M HCIO. I AM A O O ? Submit Request Answer
PT - 1L 5. K, for hypochlorous acid, HCIO, is 3.0x10-8 Calculate the pH after 10.0. 20.0, 30.0, and 40.0 mL of 0.100 M NaOH have been added to 40.0 mL of 0.100 MHCIO.
Part G Kfor hypochlorous acid, HCIO, is 3.0x108. Calculate the pH after 40.0 mL of 0.100 M NaOH have been added to 40.0 mL of 0.100 M HCIO. IVO A£¢ A A O ? Submit Request Answer
Part D K, for hypochlorous acid, HCIO, is 3.0x108. Calculate the pH after 10.0 mL of 0.100 M NaOH have been added to 40.0 mL of 0.100 M HCIO. O AQ O O ? Submit Request Answer
Part F Ka for hypochlorous acid, HCIO, is 3.0x108. Calculate the pH after 30.0 mL of 0.100 M NaOH have been added to 40.0 mL of 0.100 M HCIO. IVO ACC O O ? Submit Request Answer
Ka for hypochlorous acid. HCIO, is 3.0x108. Calculate the pH after the stepwise addition of 0.100 M NaOH (from 0 ml to 50 mL, in I mL increments) to 40.0 ml of 0.100 M HCIO. Plot your results in Excel and on the graph, identify the pH at the equivalence point and at half of the equivalence point.
5. The K, for HCIO is 3.0 x 10 calculate the pH of a solution after 10.0, 20.0, 30.0, and 40.0 mL of 0.100 M NaOH has been added to 40.0 mL of 0.100 M HCIO
ASAP please Consider the titration of 50.0 mL of 0.200 M hypochlorous acid HCIO (Ka = 3.5 x 10-8) with 0.250 M NaOH. 5- How many milliliters of NaOH are required to reach the equivalence point? a) b) Calculate the pH before titration c) Calculate the pH after adding 40.0 mL. of NaOH d) Calculate the pOH after adding 20.0 ml, of NaOH
the Ka of HClO is 3.0x10^-8 at 25C. calculate pH of a .0385 10) The K of hypochlorous acid (HCIO) is 3.0x10*at 25.0 °C. Calculate the pH of a 0.0385 M hypochlorous acid solution. A) 1.41 B) 8.94 C) 4.47 D) 7.52 E) -1.41 Answer: C 11) Determine the pH of a 0.35 M aqueous solution of CH, NH, (methylamine). The K, of methylamine is 4.4x104 A) 10.00 B) 3.86 C) 12.09 D) 1.96 E) 13.24 Answer: C
Calculate the pH during the titration of 10.00 mL of 0.400 M hypochlorous acid with 0.500 M NaOH. The Ka for HOCl is 3.0 x 10-8 M. 1. What is the pH after 7.30 mL of NaOH are added? 2. What is the pH after 12.30 mL of NaOH are added? Please use the BCA table.