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QUESTION 20 5 points Save Answer Use the information below, answer the next 2 questions: Suppose that the distance of fly bal

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Answer #1

Solution :

Given that ,

mean = \mu = 250

standard deviation = \sigma = 50

n = 49

\mu\bar x = 250

\sigma\bar x =\sigma  / \sqrt n = 50 / \sqrt 49=7.14

P(\bar x < 240) = P[(\bar x - \mu \bar x ) / \sigma \bar x < (240-250 / 7.14]

= P(z < -1.40)

Using z table

= 0.0808

=0.081

B.

ng standard normal table,

P(Z < z) = 80%

= P(Z < z) = 0.80  

= P(Z < ) = 0.80

z = 0.84

Using z-score formula  

\bar x = z * \sigma \bar x+ \mu \bar x

\bar x = 0.84 *7.14+250

=256

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