Ans :
[H+ ] = 10-pH
putting value of pH
[H+ ] = 10-1.25
[H+ ] = 0.0562 M
M = mol solute / volume (L)
0.0562 M = n / 10.0 L
n = 0.562 mol
Each mol H2SO4 gives 2 mol H+ ions , so the number of mol of H2SO4 here will be : 0.562 mol / 2 = 0.281 mol
Mass of sulfuric acid = mol x molar mass
= 0.281 mol x 98.079 g/mol
= 27.6 grams
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