A.) An aqueous solution of sulfuric acid is made by dissolving 585.0 g of sulfuric acid in enough distilled water to make a one liter solution. Calculate the molarity, the molality, the mass% and the mole fraction of sulfuric acid in this solution. The density of this solution is 1.350 g/mL. MW H2SO4 = 98.00 g/mol. Please explain!! Thank you
B.) Which substance(s) is (are) miscible in water?
For the first part we have given amount of solute and also volume of solution and density so from that information we can calculate first moles of solute and then molarity also from moles of solution and moles of solute we can calculate moles of solvent and from that we can calculate molality also mole fraction and mass percent as shown below.
Now for the second as we know the like dissolve like principal so water is polar so only polar solute be misible in water and also it depends on the length of carbon chain or it depend on hydrophobic as well as hydrophilic part as shown below
A.) An aqueous solution of sulfuric acid is made by dissolving 585.0 g of sulfuric acid...
A solution is prepared by dissolving 27.75 g sulfuric acid, H2SO4, in enough water to make exactly 200.0 mL of solution. If the density of the solution is 1.1094 g/mL, what is 1. Weight % of H2SO4 in the solution? 2. Mole fraction of H2SO4 in the solution? 3. Molarity of H2SO4 in the solution? 4. Molality of H2SO4 in the solution?
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