A solution is prepared by dissolving 17.75 g sulfuric acid, H2SO4, in enough water make 100.0 mL. What is the molarity? A) 1.940 M H2SO$ B) 0.1810 M H2SO4 C) 1.810 M H2SO4 D) 0.1775 M H2SO4
H2SO4 molar mass=98
moles of H2SO4 = 17.75/98 = 0.1811
molarity of H2SO4=moles /volume = 0.1811/0.1L = 1.810 M
hence answer is C) 1.810M H2SO4
A solution is prepared by dissolving 17.75 g sulfuric acid, H2SO4, in enough water make 100.0...
A solution is prepared by dissolving 27.75 g sulfuric acid, H2SO4, in enough water to make exactly 200.0 mL of solution. If the density of the solution is 1.1094 g/mL, what is 1. Weight % of H2SO4 in the solution? 2. Mole fraction of H2SO4 in the solution? 3. Molarity of H2SO4 in the solution? 4. Molality of H2SO4 in the solution?
A solution is prepared by dissolving 27.75g Sulfuric Acid, H2So4 in enough water to make exactly 200. mL of solution. If Density = 1.1094g/mL What is the Mole Fraction of H2S04?
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