In a group of 12 young professionals studied, it was found that they purchased on average...
In a group of 12 young professionals studied, it was found that they purchased on average $222.331 per month eating meals prepared outside the home, with a standard deviation of $33.5432. What is the 90% confidence interval of the true amount of money young professionals spend monthly on meals prepared outside the home?
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In a group of 12 young professionals studied, it was found that
they purchased on average...
In a group of 15 young professionals studied, it was found that they purchased on average...
In a group of 15 young professionals studied, it was found that they purchased on average $186.498 per month eating meals prepared outside the home, with a standard deviation of $30.392. What is the 99% confidence interval of the true amount of money young professionals spend monthly on meals prepared outside the home? 1) ( 163.138 , 209.858 ) 2) ( 183.521 , 189.475 ) 3) ( 163.372 , 209.624 ) 4) ( -163.138 , 209.858 ) 5) ( 178.651...
12 squirrels were found to have an average weight of 10.2 ounces with a sample standard...
12 squirrels were found to have an average weight of 10.2 ounces with a sample standard deviation is 0.15. Find the 90% confidence interval of the true mean weight.
Thank you for answering my question with detail. 3. A restaurant association collected information on the...
Thank you for answering my question with detail.
3. A restaurant association collected information on the number of meals eaten outside the home per week by young married couples. A survey of 20 couples showed the sample mean number of meals eaten outside home was 2.76 meals per week, with a S.D. of 0.75 meals per week. Construct a 90% confidence interval for the population mean. Construct a 99% confidence interval for the population mean. If the population standard deviation...
2) In a hospital, a random sample of 12 weeks was selected, and it was found...
2) In a hospital, a random sample of 12 weeks was selected, and it was found that an average sample of 537 patients were treated in the emergency room each week. The standard deviation was 21.82. Assuming that the variable is normally distributed, find the 90% confidence interval of the true mean. 90% confidence interval:
as 2009 Mansour conducted a survey to estimate the average number of the hours studied weekly...
as 2009 Mansour conducted a survey to estimate the average number of the hours studied weekly by college students. He chose random sample of 16 students and found that the average time they study weekdy was 15 hours with a standard deviation of 2 hours. (10 marks) a. What is the point estimate of the population mean? b. Which Test should Mansour use to find the mean confidence Interval (t or Z). Justify your answer? c. Using the 90% level...
Question 1 (1 point) A customer wants to estimate the average delivery time of a pizza...
Question 1 (1 point) A customer wants to estimate the average delivery time of a pizza from the local pizza parlor. Over the course of a few months, the customer orders 29 pizzas and records the delivery times. The average delivery time is 23.69 with a standard deviation of 7.212. If the customer estimates the time using a 95% confidence interval, what is the margin of error? Question 1 options: 1) 0.7137 2) 2.2782 3) 2.7433 4) 1.3392 5) 2.739...
An educational research group wants to know how many hours college students spend studying outside of...
An educational research group wants to know how many hours college students spend studying outside of class per week. If they survey 100 students and find an average 10.5 hours of studying a week, with a standard deviation of 2.25, find a 98% confidence interval for the true average number of hours spent studying. Answer choices: 10.5±.324 10.5±.225 None of these 10.5±.482 10.5±.524
Many medical professionals believe that eating too much red meat increases the risk of heart disease...
Many medical professionals believe that eating too much red meat increases the risk of heart disease and cancer. Suppose you would like to conduct a survey to determine the annual consumption of beef by a typical American and want to use four pounds as the desired margin of error for a confidence interval of the population mean. Assume the population standard deviation is 20 pounds. Determine the sample size when: a)A 90% confidence interval is desired for the mean amount...
1. To determine the average number of hours spent studying by college students per week, a...
1. To determine the average number of hours spent studying by college students per week, a sample of 39 students was randomly selected, and found to spend an average of 17.1 hours per week, with a standard deviation of 4.3 hours. Find the 90% confidence interval for the mean number of hours spent studying per week by all college students. What is the upper and lower bound? 2. If I asked a random student how many hours they study per...
the average grade of a group of 24 alegbra students is 85%, and the standard deviation...
the average grade of a group of 24 alegbra students is 85%, and the standard deviation is known to be 4%, find the 95% confidence interval for the true mean of the grades
Thank you for answering my question with detail.
3. A restaurant association collected information on the number of meals eaten outside the home per week by young married couples. A survey of 20 couples showed the sample mean number of meals eaten outside home was 2.76 meals per week, with a S.D. of 0.75 meals per week. Construct a 90% confidence interval for the population mean. Construct a 99% confidence interval for the population mean. If the population standard deviation...
2) In a hospital, a random sample of 12 weeks was selected, and it was found that an average sample of 537 patients were treated in the emergency room each week. The standard deviation was 21.82. Assuming that the variable is normally distributed, find the 90% confidence interval of the true mean. 90% confidence interval:
as 2009 Mansour conducted a survey to estimate the average number of the hours studied weekly by college students. He chose random sample of 16 students and found that the average time they study weekdy was 15 hours with a standard deviation of 2 hours. (10 marks) a. What is the point estimate of the population mean? b. Which Test should Mansour use to find the mean confidence Interval (t or Z). Justify your answer? c. Using the 90% level...
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