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4. A 1000-kg satellite in circular orbit around the Earth is moving at a speed of 7 x 10 m/s. How much work must be done to
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Answer #1

Speed of satellite in orbit,

v = sqrt(GM/r)

7e3 = sqrt(6.67e-11*5.972e24/r)

r = 8.129e6 m

height h = r-R = 8.129e6 - 6.371e6 = 1758000 m

new orbit r2 = R+2h = 6.371e6+2*1758000 = 9887000 m

work done by external agent = change in mechanical energy = -GMm/2r2 + GMm/2r1

= -6.67e-11*5.972e24*(1000/2)*(1/9887000 - 1/8.129e6)

= 4.356*10^9 J answer

  

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