What is the wavelength (in nm) of the line in the spectrum of the hydrogen atom that arises from the transition of the electron from the orbital with n =6 to the orbital with n = 3?
Here photon will be emitted
1/lambda = R* (1/nf^2 - 1/ni^2)
R is Rydberg constant. R = 1.097*10^7
1/lambda = R* (1/nf^2 - 1/ni^2)
1/lambda = 1.097*10^7* (1/3^2 - 1/6^2)
lambda = 1.094*10^-6 m
lambda = 1094 nm
Answer: 1094 nm
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