Question

(E4B.3(a) By how much does the chemical potential of copper change when the pressure exerted on a sample is increased from 100 kPa to 10 MPa? Take the mass density of copper to be 8960 kg m ?

Answer 1

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Given that,

Change in pressure is given by,

AP= P2 - Pi = 10 MPa – 100 kPa

:: AP= (10 x 106 Pa) -(100 x 103 Pa)

... ΔΡ = 9.9x 106 Pa

1 Mpa = 10⁶ Pa

1 kPa = 10³ Pa

Molar mass of Copper, M= 63.55 g/mol =63.55 x 10^-3 kg/mol

Density of the metal,

D = 8960 kg/m3

Therefore, Change in chemical potential is given by,

9.9 x 106 Pa Au= M. P = (63.55 x 10-kg/mol) * 3960 kg/m3

:Δμ = 70.2 J/mol

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