WORKING NOTES: | CALCULATION OF THE DEPRECIATION AS PER STRAIGHT LINE METHOD | ||||
Purchase Cost of Machine | $ 13,00,000 | ||||
Less: Salvage Value | $ 1,40,000 | ||||
Net Value for Depreciation | $ 11,60,000 | ||||
Usefule life of the Assets | 8 years | ||||
Depreciation per year | $ 1,45,000 | ||||
Cash Flow per year = Net Income + Depreciation | |||||
Cash Flow per year = $ 130,000 + $ 145,000 | |||||
Cash Flow per year = $ 275,000 | |||||
SOLUTION : 1 | |||||
CACLULATION OF THE PRESENT VALUE WITH COST OF CAPITAL @ 10% | |||||
Years | Cash Outflow / Inflow | PVF of $ 1 @ 10% | Present Value (A XB) | ||
0 | -13,00,000 | 1.00 | $ -13,00,000 | ||
1 | 2,75,000 | 0.9091 | $ 2,50,000 | ||
2 | 2,75,000 | 0.8264 | $ 2,27,273 | ||
3 | 2,75,000 | 0.7513 | $ 2,06,612 | ||
4 | 2,75,000 | 0.6830 | $ 1,87,829 | ||
5 | 2,75,000 | 0.6209 | $ 1,70,753 | ||
6 | 2,75,000 | 0.5645 | $ 1,55,230 | ||
7 | 2,75,000 | 0.5132 | $ 1,41,118 | ||
8 | 2,75,000 | 0.4665 | $ 1,28,290 | ||
8 | 1,40,000 | 0.4665 | $ 65,311 | ||
Present Value | $ 2,32,416 | ||||
SOLUTION : 2 | |||||
IRR of the project is greater than 10% because net present value of the project @ 10% is positive. | |||||
Answer = Greater than 10 Percent | |||||
SOLUTION : 3 | |||||
CACLULATION OF THE PRESENT VALUE WITH COST OF CAPITAL @ 13% | |||||
Years | Cash Outflow / Inflow | PVF of $ 1 @ 13% | Present Value (A XB) | ||
0 | -13,00,000 | 1.0000 | $ -13,00,000 | ||
1 | 2,75,000 | 0.8850 | $ 2,43,363 | ||
2 | 2,75,000 | 0.7831 | $ 2,15,365 | ||
3 | 2,75,000 | 0.6931 | $ 1,90,589 | ||
4 | 2,75,000 | 0.6133 | $ 1,68,663 | ||
5 | 2,75,000 | 0.5428 | $ 1,49,259 | ||
6 | 2,75,000 | 0.4803 | $ 1,32,088 | ||
7 | 2,75,000 | 0.4251 | $ 1,16,892 | ||
8 | 2,75,000 | 0.3762 | $ 1,03,444 | ||
8 | 1,40,000 | 0.3762 | $ 52,662 | ||
Present Value | $ 72,324 | ||||
Answer = $ 72,324 | |||||
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