Question

Be sure to answer all parts. Enter your answer in scientific notation. = 212 kJ/mol for the Calculate the pressure of o, in atm) over a sample of NiO at 25.00°C if AG reaction. For this calculation, use the value R= 8.3144 J/K'mol. Nio(s) = Ni(9) +-026) * 10 atm

Answer 1

Answer = 3.83*10^13 atm.

the detailed explanation is shown below.

We have been given the Equation,

NiO(s) -------> Ni(s) + 1/2O2(g)

Now, note down the given information, and unit conversion,

∆G°= 212 KJ/mol

T= 25 + 273 =298 K

R= 8.314 J/Kmol = 0.008314 KJ/mol.

We know the relationship between ∆G and R,T

∆G = ∆G° + RTlnQ

At equilibrium ,∆G=0 and Q becomes K,

Therefore, ln K = ∆G°/RT

Putting the data ,

lnK = 212KJ/mol / 0.00831 KJ/K.mol *298 K

lnK= 212/0.247638 = 85.608

taking anti log both sides,

K = e^85.608 = 1.51*10^37

Now , from the given reaction, we see,

K=[ pO2]^1/2

pO2 = √1.51*10^37 = 3.88*10^18 Pa

Changing from Pascal to atm,

since , 1 Pascal= 9.869*10^-6 atm

So, 3.88 *10^18 Pa= 3.88*10^18* 9.869*10^-6.

=38.34*10^12atm

In scientific notation,

= 3.83*10^13 atm.

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