Question

1. Show all your work calculating the # of Cs based on the Mand (M+1] peaks. 2. Based on the mass spectrum, do you think you
Compound 14 is a liquid (b.p. 85) which finds its greatest application as an aprotic solvent UV-transparent; IR-liquid fim.




Mass Spectrum MASS SPECTRAL DATA Unknown mle (MM) 90 91 92 Relative Intensity 18.4 0.83 0.09 Intensity m/e
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Answer #1

1. No of carbons can be calculated from the relative intensity of [M+1] peak.

We have

Intensity of M+ peak (90) = 18.4

Intensity of [M+1] peak (91) = 0.83

We should make up the molecular ion peak to 100 % intensity to calculate the % abundance of [M+1]

Thus

if 18.4 intensity is 100 % then

0.83 intensity

(0.83/18.4) x 100 = 83/18.4 = 4.51 %

Thus the percentage abundance of [M+1] peak = 4.51 %

Now, we have the formula to calculate number of carbons

No. of carbons = % abundance of M+1 peak / 13C abundance %

We have % abundance of 13C = 1.1

Therefore the number of carbons = 4.51 / 1.1 = 4.1 \approx 4

Thus the required number of carbons from M+ and M+1 peaks = 4.

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