Question

Intensity MASS SPECTRAL DATA Unknown m/e Relative Intensity Mass Spectrum (мм) 90 18.4 0.83 92 0.09 29 90 I5 60 m/e

Answer 1

19 number of carbons present in the compound can be calculated by following formula - number of carbons = carbon % of M+1 peak relative to mt XIOD F 18.4 Relative intensity of mt = 18-4 • M+I = 0.83 % of mtl compared to mt peak = 0.83 x 100 ZP4.51) number of carbons = 4.511 = 4 compound contains '4 carbon atoms. =

& compound contains '4' carbon atoms. → The presence of M+2 indicates the presence of oxygen atom(s) in our compound. - only o sid, Br contribute to Mt2 peak we cann't confirm the preferice of s/d/or as our compound's molar mass is only 90. → According to nitrogen rule, as our compounds molar mass is 90, which is an even number, which implies the possibility of o or even number of nitrogens.

two if we consider at least one Oxygens, then 90- (4x12) - (2x 16) = 10, so we cann't accomodate two Nitrogens. Answer: No, compound doesn't contain . Nitrogen atoms) 3 a number carbons = 4 number of oxygens = 2 number of Hydrogens = 90-(4x12)-(2X16) = 10 molecular formula: C4H1002

I b) if we consider the presence of two n's (C4N₂ H14 possible molecular formula : C4H10O, Cy Ny Hiy & Exact mass of parent in =90 Cy Hiog is more likely because we cann't arrange 14 H's on & C's & 2N's